69. 성격 유형 검사하기

 

using System;

public class Solution {
    public string solution(string[] survey, int[] choices) {
        string answer = "";
        int R = 0;
        int C = 0;
        int J = 0;
        int A = 0;

        for (int i = 0; i < survey.Length; ++i)
        {
            if(survey[i] == "RT") R += Add(choices[i], R);
            else if(survey[i] == "TR") R -= Add(choices[i], R);
            else if (survey[i] == "CF") C += Add(choices[i], C);
            else if (survey[i] == "FC") C -= Add(choices[i], C);
            else if (survey[i] == "JM") J += Add(choices[i], J);
            else if (survey[i] == "MJ") J -= Add(choices[i], J);
            else if (survey[i] == "AN") A += Add(choices[i], A);
            else if (survey[i] == "NA") A -= Add(choices[i], A);
        }

        if (R >= 0) answer += "R";
        else answer += "T";

        if (C >= 0) answer += "C";
        else answer += "F";

        if (J >= 0) answer += "J";
        else answer += "M";

        if (A >= 0) answer += "A";
        else answer += "N";

        return answer;
    }
    
    public int Add(int choice, int type)
    {
        if (choice == 1) type = 3;
        else if (choice == 2) type = 2;
        else if (choice == 3) type = 1;
        else if (choice == 4) type = 0;
        else if (choice == 5) type = -1;
        else if (choice == 6) type = -2;
        else if (choice == 7) type = -3;

        return type;
    }
}